# How do you find the vertices and foci of #36x^2-10y^2=360#?

##### 1 Answer

Nov 17, 2016

The vertices are

The foci are F

The equations of the asymptotes are

#### Explanation:

Let's rewrite the equation

Divide by 360

This is the equation of a right left hyperbola

The center is

The vertices are

To calculate the foci, we need

The foci are F

The slope of the asymptotes are

The equations of the asymptotes are

graph{(x^2/10-y^2/36-1)(y-6/sqrt10x)(y+6/sqrt10x)=0 [-28.87, 28.87, -14.44, 14.44]}