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Comments 101 to 125 out of 179:

101. Bob Lacatena at 00:29 AM on 10 January, 2013
     high treason, A brief word of advice. "Thought experiments" such as yours often yield "obvious" and "logical" results. This comes in part because it is so easy and obvious, which in turn is because it is able to ignore a lot of inconvenient details, like actually doing the math, or establishing a source of energy. In your case, consider that while compression of a gas may heat that gas, after the compression stops, and the gas radiates its heat away, additional energy is required to maintain that temperature. The simple act of keeping the gas under pressure does not maintain the temperature. Ah ha, you say, but what about the sun? Yes, no matter how you define the system, the sun keeps the planet at an average radiating temperature consistent with the energy absorbed (255K). The problem then becomes, in your model, to determine where the temperature thresholds are, and how the planet radiates energy as a 255K body, while maintaining much higher temperatures at the surface of the earth. Unfortunately, when you actually do the math, you will find that your theory fails. The temperature at the surface would be nowhere near the actual temperatures that we see. Therefore, some other factor is at work. Gee, I wonder what that is?
102. curiousd at 13:02 PM on 12 January, 2013
     This last comment by Sphaerica leads me to check out with you folks my latest delving into Modtran as an educational tool. 1. Used default settings except looking down from 16 km. This means above most convective heating (Forster 1997).I have found that at equator 17 km is about coolest atmospheric layer. 2. My plot of the change in outgoing flux per doubling of CO2 also had a maximum at 16 km, using 1 km increments. 3. At 17 km the narrow, by Doppler, not pressure, broadened, upward going emission peak due to upper atmospheric CO2 had become manifest in the saturation region of the bending mode absorption. So another reason to stop at 16 km. Default CO2 is 375 ppm. No relative humidity. 4. Using a digitizing program I measured the areas under the 260 K black body peak AND the computed absorption spectrum including the large bending mode dip and the smaller ozone, H2O contributions. I use the 260 K curve to correct the real curve for issues in correctly digitizing the high and low wave number limits. Both curves integrate to a bit under the Stefan Boltzman formula if we assume 260 K but the real curve is definitely somewhat greater in equivalent temperature than 260 K I am using as a reference. I don't think the real curve corresponds to over 265 K but I cannot take the time to get really good statistics, and this is digitizing by eyeball. 5. Conclusion.....Yes indeedy, the earth looks - from the Modtran vantage point of 16 km - like a 260 plus something K black body in the tropics. Not unreasonable that integrated over the globe one might thusly get 255 K? I am interested in developing a lab exercise thereby. Comments?
103. curiousd at 19:10 PM on 12 January, 2013
     Further digging around leads me to conclude that the 265 degrees I get in tropics using Modtran for an "effective" radiating temperature is about right. Maybe I am starting to get this stuff.
104. Wig4 at 10:01 AM on 13 January, 2013
     "Intermediate" level article copy contains this passage : quote ...//... A glass greenhouse works primarily by blocking convection, and an atmospheric greenhouse works primarily by blocking thermal radiation, and so the comparison is not exact. ...//... This is blatantly wrong information. (1) ((A glass greenhouse works primarily by blocking convection)) Nonsense. Glass greenhouse works promarily by blocking IR with wavelenght above 3000 nm from leaving. (This is related ti SiO2 glass, other glass-types have different IR-block out limits) It's reflected inward again. This causes partial reabsorption by solid materials, re-emitting IR, reflected again, and again and again in this enclosed space, until losses are getting effective through conduction. (air-glass-air, and I calculate these loss rates 'everyday' through my practise... 99,9% correctly calculable...) Convection originating from air-contact with the solids is heating the air, not the radiation. That is the glass-glasshouse effect. Of coarse the heated air will leave if you open windows, but that if childish talk when explaining physics of the greenhouse effect. The total heat capacity contained in the enclosed air, however, is futile compared to the heat capacity of the solids. That explains the extreme speed of the glass-greenhouse effect. Ventilation of a greenhouse will lower very little of the temperature gain on the solids. The re-re-reflexion mechanism is still working. Only the air temperature, by ventilation, is fooling us we broke down this greenhouse effect. Nonsense, it goes on. We're only evacuating the resulting air convention heat, witch has, as said, a very low heat capacity. (Only water vapour contains a higher heat capacity, due to it's latent heat energy content, not temperature.) I'm really shocked to find such nonsense written down in presumed "intermediate what science says". Because science never said such a thing. Where is that article sourced? A journalist's sensation box ? .... By the way, I see Ned and others, all over this discussion, play with the notion quote ...//... confused about the distinction between "near infrared" and "thermal infrared" wavelengths ...//... While these terminologies are rather useless in science, when describing thermodynamic processes. We quantify only, we don't play with words. (This whole discussion lacks quantification, btw.) Sun radiation boosts a serious amount of direct molecule activating IR-radiation (roughly 1000 - 5000 nm), from which up to 3000 nm is passing glass. At the total 45% IR present in sunlight, at least 30% is contributing to direct molecule vibration activation, "heat". Because this depends to the receiving molecule, the global % contributing directly to heat excitation from the sunlight is not exactly definable. Earth-born IR-radiation peeks at about 10,000 nm, but starting only over 2500 nm. This explains fully the "trap" of reflexion behind Si02 glass. (2) ((an atmospheric greenhouse works primarily by blocking thermal radiation)) Nonsense again. Atmospheric "greenhouse" (fake terminology use, grown over the years.... never use the same terminology for 2 totally different physical systems...) works primarily by absorption of IR-radiation. In some stage of this discussion, I saw the 100% correct statement that all molecules of whatever kind, within a gas mix, in one location, equalise onto the exact same temperature, though the collisions among each other. This means, that if one kind of molecule warms up faster then another kind of molecule, related to a specific IR waverlenght, the resulting accumulated heat is extremely fast redistributed over all at random neighbour molecules. First physical concern is = available heat capacity of the mixed gas. (This capacity always if futile, compared with solids on earth. Only the watervapour ice cristals physics provide something of non-futile proportions) If RE-emitting of radiation (different wavelenght, in most cases ?) is happening, now, the original captator is in minority position within the total gas composition (including suspended ice crystals.) As said, RE-adiation can happen in all kind of different wavelenghts, through this mechanism. I like to see proven measured quantifications within this real-reality complex process, not wet-finger work.) Apart from RE-radiation, chemical driven heat converting processes can take place. On this level , all 5 heat dissipation mechanisms are active at the same time. Convection, conduction, radiation, latent energy conversion, chemical energy conversion. I read zero.dot.zero comments, until now about this complex reality. (From both sides of the discussion table, by the way.) I'm not an active scientist. I have studied, however, thermodynamics, in my accademic years, and I feel horror when anyone is talking gibberish within this domain. I read ridiculous theoretic simplicications of those very complicated thermodynamic processes within the so called "peer revieuwed scientific majority", and I encounter just as much riduculous stupidities from the opposition side. It is sad. Fact is that at least all basic laws of thermodynamics have been proven correct. (-snip-) Anyway, greetings to all, and my wish to get this into real science backed discussion. (I just touched a microscopic detail within the whole topic... ;-) )
     Response: [DB] Please familiarize yourself with this site's comments policy (link adjacent to the comment box). All caps usage is forbidden (converted to lower case in this instance; future violations will ensure moderation up to and including deletion of the entire comment). Inflammatory tone snipped.
105. Tom Curtis at 14:30 PM on 13 January, 2013
     Wig4@104: 1) A variety of experiments have been performed by people attempting to quantify the strength of the effect of trapping IR radiation by glass in warming greenhouses. Most famously, this was done by R. W. Wood in 1909, who found no measurable effect. The lack of measurable effect has been misinterpreted by Wood and others as a refutation of the atmospheric greenhouse effect. In fact, while some have repeated Wood's experiment and found no measurable effect, others have found a 15 to 20 degree C increase in temperature relative to control when trapping IR radiation. That 15-20 degrees C is, however, less than half of the total increase in temperature. Further, in greenhouses in which the presence of vegetation limits the increase in temperature of the surface, and hence the increase in IR radiation from the surface, the effect will be even smaller. It follows that the prevention of air circulation carrying away excess heat is the major cause of increased temperatures in greenhouses. Ergo, greenhouses primarily work by "by blocking convection" as indicated in the original article. 2) Your argument devolves down to a mixture of garbled facts and outright errors. Let's start with the basics: a) The total upwelling IR flux at the surface is greater than the incoming SW flux times (1-albedo); b) The total upwelling IR flux at the Top Of the Atmosphere (TOA) approximately equals the incoming SW flux times (1-albedo). c) The difference between the upwelling IR flux at the surface and that at the TOA is the atmospheric greenhouse effect; and it can only exist because components of the atmosphere absorb IR radiation from below (lower atmosphere and or surface). c') If components of the atmosphere did not absorb IR radiation, then by necessity the upwelling TOA IR flux would equal or exceed that at the surface, resulting in no atmospheric greenhouse effect. c") If the atmosphere did not absorb more upwelling IR radiation from the surface than the atmosphere alone emitted at the TOA, then by necessity the upwelling TOA IR flux would equal or exceed that at the surface, resulting in no atmospheric greenhouse effect. c"') If the atmosphere absorbs more more upwelling IR radiation from the surface than it alone emits at the TOA, then be necessity the upwelling TOA IR flux will be less than that at the surface, and hence there will be an atmospheric greenhouse effect. From the points above, it is clear that atmospheric absorption of IR radiation is necessary for the existence of an atmospheric greenhouse effect. Ergo, as a simplified account, saying that the "atmospheric greenhouse works primarily by blocking thermal radiation" is sufficiently accurate. Radiation of IR radiation by the atmosphere reduces the strength of the atmospheric greenhouse effect, and in the special and unusual case where the atmosphere is warmer than the surface, will result in a cooling of the surface. Typically, however, the atmosphere is cold enough that there is a substantial atmospheric greenhouse effect, and the colder the atmosphere the stronger that effect will be. I refer you to my article, Warm Earth, Cold Atmosphere for a more detailed discussion, including examples of "proven, measured quantifications" of this effect. Finally, I note that IR radiation from the atmosphere is restricted in the range from which it will radiate, with a large a smaller atmospheric window from which there is essentially no radiation (or absorption) except in the presence of clouds. Further, I will note that the atmospheric greenhouse effect is so-called for historical reasons, and nothing save a foolish pedantry is served by railing against history.
106. Bob Lacatena at 06:04 AM on 14 January, 2013
     Wig4, ...short version of Tom's answer... A greenhouse works by interfering with both infrared radiation and convection, but the important point with reference to the topic at hand is convection. You are taking umbrage at the use of the word "block" in place of "absorption." That's just picking nits, and the use of the latter term does not better clarify the argument for the reader. To the sort of person reading the Intermediate rebuttal, the term "blocked" is perfectly clear, especially when considered in concert with the graphic presented. It's about communication.
107. Bob Loblaw at 06:51 AM on 14 January, 2013
     To add: - plastic greenhouses (which don't block any IR) work pretty well, so it can't be the IR that keep things warm. - glass greenhouses, in which the glass does affect IR, tend to reduce the incoming solar more than they increase incoming IR, once the glass gets typically dirty. So, the net effect of the glass on radiative input tends to be negative for dirty glass. - all the latent heat that results from evaporating water in the greenhouse soil is kept inside (unless vented). Greenhouses are awfully humid, in addition to being warm.
108. rugbyguy59 at 17:09 PM on 13 February, 2014

     A new variant of this has appeared on Goddard's blog. A guy, recently retired and so now "free to talk" (although he still writes under a pseudonym), who claims to be an infrared astronomer is saying that IR at the CO2 wavelength can't warm the Earth.

     He says "In all the bands that are responsible for back radiation in the brightness temperatures (color temperatures) related to earth’s surface temperature (between 9 microns and 13 microns for temps of 220K to 320 K) there is no absorption of radiation by CO2 at all. In all the bands between 9 and 9.5 there is mild absorption by H2O, from 9.5 to 10 microns (300 K) the atmosphere is perfectly clear except around 9.6 is a big ozone band that the warmists never mention for some reason. From 10 to 13 microns there is more absorption by H2O. Starting at 13 we get CO2 absorption but that wavelength corresponds to temperatures below even that of the south pole. Nowhere from 9 to 13 microns do we see appreciable absorption bands of CO2."

     So obviously I'm not buying into the overturning of years of well tested science by some anonimous conspiracy theorist on a blog and ask those who mention it to tell me when he's publishing his paper or for a scientific reference where I can check his claims. On the other hand I wouldn't appreciate if someone could give me a more scientific understanding of why he is wrong. Always looking to learn.

109. scaddenp at 17:40 PM on 13 February, 2014

     Sigh, it is pretty hard to take Steve "Co2 falls as snow in Antarctica" Goddard seriously. Now its conservation of energy is wrong? It pretty hard to make sense of what he is saying - I dont think he knows. However, there is excellent series taking you through the text book details at Science of Doom.

110. Dikran Marsupial at 18:45 PM on 13 February, 2014

     rugbyguy59, that argument demonstrates a fundamental lack of understanding of the greenhouse effect.  The Earths energy budget is determined at the top of the atmosphere by the temperature of the atmosphere at the height at which outbound IR is no longer absorbed by CO2.  The lapse rate means this is much colder than the surface.  As we add more CO2 the height of this layer rises, which means that the radiating layer is colder and hence radiates less energy.  The Earth as a whole then gains heat until the temperature of the radiating layer warms enough for the radiated energy to be high enough for the energy budget to be balanced. 

     Now, as the atmosphere as a whole warms, it will radiate heat at a range of frequencies, because it is due to the heat of the atmosphere as a whole, not just the IR radiated from CO2.  So of course it isn't all at the absorption bands for CO2.

     Gilbert Plass worked out the details of this back in the 1950s.

111. sailingfree at 11:05 AM on 25 February, 2016

     Direct evidence of CO2 causing warming is in the following news article and original paper.
     http://newscenter.lbl.gov/2015/02/25/co2-greenhouse-effect-increase/
     http://www.nature.com/nature/journal/v519/n7543/full/nature14240.html
     The above describe direct measurement of the incoming and outgoing radiation of the Globe at various wavelengths over a decade, and show that warming is directly due to more CO2.

     Response:

     [PS] Fixed link. Please learn to do this yourself with the link button in the comments editor.

112. ConcernedCitizen at 21:32 PM on 28 April, 2016

     "the moon’s surface reaches 130 degrees C in direct sunlight at the equator"

     So GH gasses and the GH effect reduce maximum temperature too.

113. Tom Curtis at 22:41 PM on 28 April, 2016

     ConcernedCitizen @112, no.  Rather, the equalization of temperatures by the distribution of energy (by the atmosphere and ocean) reduces maximum temperatures and increases minimum temperatures - as anybody knows who compares maximums and minimums in a desert with those on the coast.

     And in case you are wondering, the estimated 33 C increase in Global Mean Surface Temperature due to the Earth's greenhouse is relative to a situation with perfectly distributed energy on the surface (ie, all points are the same temperature, whether polar or equatorial, and whether day or night).  That means it is an under estimate of the temperature impact of the greenhouse effect.

114. MA Rodger at 22:50 PM on 28 April, 2016

     ConcernedCitizen @112.

     Another take on answering your question.

     Sort of yes, but only a little bit of that implied by the moon's maximum temperatures. The main reason the moon reaches 130ºC is because it has a 655 hour rotation so the equatorial moon surface is being heated by sunlight for 2 weeks at a stretch rather than the 12 hours here on Earth.

     A quick look at some max/min temperatures for places on the Earth's equator shows a difference of about 10ºC night to day. This is an air temperature. I would imagine rock temperatures on Earth (which is the equivalent of what is being measured on the moon) would show a greater variation. Looking at a graph of moon surface temperatures, the moon temperature rises from 300K something like 40ºC in 12 hours.

     Part of the reason for extra heating on the moon will be because our atmosphere reflects away sunlight as well as also absorbing sunlight before it reaches the ground (famously the UV component of sunlight). The atmosphere also cools the surface through evaporation and conduction/convection. I'm not sure that any of these mechanisms would be called a "GH effect" but rather the effect of having an atmosphere.

115. fake reality at 19:18 PM on 19 July, 2016

     @111 Without reading the links I suspect that they are about spectral signs of absorption from co2?

     The strange thing with co2-theory is that a massive decrease in spectral intensity is interpreted as increase in temperature.  That is a direct opposite of how spectral intensity works. A decrease in intensity by co2 absorption is a decrease in temperature. There is no way around that. Any heating at any level must show up as an increase in intensity. Heat doesn't hide 

116. fake reality at 20:34 PM on 19 July, 2016

     @113

     The 33 degrees you point at as a proof for the greenhouse effect is enirely a product of lacking understanding of the physics in radiation and heat. I will show you why.

     If we use measured values from real observations of solar irradiation at the surface, we find that 1000W is a median value when we look at variations from pole to pole.

     If we use that, the real value of irradiation, and an emissivity of 0.8 derived from measured surface flux OLR, we get:

     1000W is 800W transformed into heat in the surface. Since only half of the surface is heated we must divide this in 2. So, 800W/m^2/2m^2  gives 400W OLR. Which fits very nicely with the average temperature of about 290K. Without even have entered the atmospher on it´s way to space.

     
     So, when we calculate radiative flux from the surface with measured real values, we can see that the surface temperature has no room for any greenhouseeffect.

      

     The reason is that you use an average flux density that is wrongly calculated by using TOA irradiation/m^2 and divide by four. That gives a surface flux equivalent to 4 small weak suns which heats a m^2 with an intensity of 259W, when the surface cools with a flux of 390W.

     Do you see the difference? The problem comes from the fact that flux and temperature is not linear but logarithmic. Four suns with a flux that adds upp to the same wattage as one sun can not heat the surface as much as the one sun in reality does.

     You use a deeply flawed approach to solar irradiation flux when you average to a value that we know is wrong according to measurements. It totally ignores that the connection between flux and temperature is non-linear.

     You use values in a calculation that gives a temperature of 255K, which is wrong according to measurements that show 288K, and then you apply a greenhouseeffect to cover up the difference. No other explanation than the difference of 33 degrees is given to show how this rise in temperature from greenhousegasses occur. There are no calculations that show how icecold gas can heat a warm surface, other than your calculation of surface temp that give the wrong temperature compared to measured values.

     I think that by using measured real values as I did, and arriving at pretty much exactly the right temperature without any fictive greenhouseeffect, before it even has entered the atmospheric gasvolume, I have proven that there is no greenhouseeffect.

     Remember that you calculation uses values of flux that is not real, they don´t exist anywhere as a value of irrradiative flux density, and that I use a value that is measured in reality. In my calculation the numbers fit perfectly, in yours there is need for a fudgefactor.

     There is a big difference in how you treat radiation when you calculate temperature. You must pay attention to the relationship between Watt and K, only if you do that you realize why the model you use get the wrong value of 255K.

     
     If you think about it, 4 suns around the earth that radiates @255K in 4m^2, will only heat 1m^2 to 255K.

     But one sun heating 1m^2 @ a median 1000W, which is a real measured value, will heat 2m^2 to 290K.

     I´m pretty proud of this point I´m making. I think I have just proven that there is no greenhouse effect.

117. fake reality at 21:03 PM on 19 July, 2016

     @114

     That is not correct. The reason that surface temp of the moon under irradiation is 130C, is that it gets 1370W/m^2 of flux density. (1370/0.0000000567)^0.25=394K. That is 121C. Right?

     You see that there is no need for any other explanations. I cannot understand why you include night temperature in a calculation of heating from solar irradiation? The night side is not irradiated, why should that be taken in to the calculation of the effect of irradiation?

     Mean temperature is a useless value in radiative heating of a surface, it is a measure of cooling, not heating. And it is the result of adding colling to heating for a net value.

     On earth we are lucky enough to have an atmosphere that evens out the mean temperature by cooling irradiated surface area with air that distributes the heat in every heated point to the whole volume of the atmosphere. Sure, we get a higher night temp but that is the result of cooling, not warming. The surface of the earth would be 394K without an atmosphere. No one kan argue the fact that irradiative flux density is lowered by the atmosphere. Solar irradiation is what heats the earth, if that is lowered by the atmosphere it means that the atmosphere cools the earth.

     That is the No Bullshit Approach that is the beauty in using real measured values.

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118. fake reality at 21:46 PM on 19 July, 2016

     @105

     I don´t want to call you a liar so instead i say that your words does not tell the truth.

     a)  The surface receives about 1000W/m^2 of solar irradiation flux. It emits about 400W. There is no way around that other than using methods that gives values that is not real.

     b) Flux at TOA is not 1370W/m^2 in average. Not 1000W or 400W either. So you are not telling the truth. Sure, it may add up to your fictive values, but those does not correlate with observations and can be disregarded as they must be wrong.

     c) I can see no argument here. You are saying that a decrease in spectral intensity is a sign of rising temperature. That is as wrong as it can get. If the atmosphere shows an effect on flux that is decreasing intensity, that means that the atmosphere is cooling. You mus pay attention to the fact that absorption is not the same as emission. Only increased emission that gives increased temperatur/flux density, is a sign of heating. Only that. Heat doesn´t hide.

     It is not a sign of warmer surface if the tropopause show that co2 decreasing intensity in spectral flux. Co2 shows that it effectively keep tropopause flux in peak wavelenghts down to a 220K balckbody curve. What you see is the bottom regulator of the temperature in the atmosphere. Co2 makes sure that tropopause keeps its temperature @ 220K, according to spectrum.

     Since we all know that it radiates equally both up and down, we can be sure that 220K is the contribution downwards as well. Not very hot, don´t you think?

     c´) If co2 was increasing temp we would see an increase in those wavelenghts that it absorbs. Are you aware of that heat can be absorbed and transformed into lower temperature?

     That happens when it takes more heat for the absorbing body to reach the same temperature. And we know that co2 radiates at 220K, so it apparently will not heat up unless it gets a lot more energy. That could be an effect from the molecule colliding with other gasses and dissipating the energy. It doesn´t matter, the measured spectrum at TOA is proof of co2 cooling, not heating.

     c´´´) In heat transfer the rate of transfer is the difference in T. The smaller the difference, the slower transfer we get. The hot body that transfer heat to the cold body is not affected by the rate of transfer. It keeps the same T all the way up to when the cold body reaches the same T, and then there is no measurable transfer.

     I like photons as much as anyone, but we know from experimental evidence that they must not be included in heat transfer. Because a hot body does not change it´s temperature because a cold body absorbs heat from it´s radiation field.

     That is, a hot body does not get warmer because a cold body is colder.

     And you are right, it is necessary for the greenhouse effect to have cold IR-radiation adding to surface temp. But it is not necessary for reality.

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119. fake reality at 22:13 PM on 19 July, 2016

     @113

     As I have shown in my other posts, No.

     The 33 degrees is entirely a product of you using 4 weak suns irradiating 4m^2 with the intensity of 290W/m^2. Since the surface is heated with an intensity of almost 400K/1000W transformed into heat equivalent to 400W/2m^2 with a surface emissivity of 0.8, the 33 degrees is a product of imagination. Or just flawed application of physics.

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120. fake reality at 22:15 PM on 19 July, 2016

     Edit in 119:

     That should of course be 400W*2m^2 of surface heat from irradiation of 1000W/m^2.

121. MA Rodger at 00:47 AM on 20 July, 2016

     fake reality @115-120.

     Hurrah! I thought the theory of a flat Earth was behind us but evidently not with you. @116 you tell us "Since only half of the surface is heated we must divide this in 2."  This can only mean you subscribe to a flat Earth. It is truly fantastic to see such a wonderful theory maintained in the face of modern science. Well done you!!

     @177 you address my comment @114 that concerns Lunar temperature. You declare that I am "not correct" (which is thankfully less strongly put than some of your other comments @115-120) and provide what you describe as "the No Bullshit Approach" which perhaps may be some terminology used by 'flat Earth' theory? I am also in the dark over your comment about the "using real measured values." Who is/is not using such values?

     The 130ºC quoted @114 is a rough value and not the measured temperature which would likely be nearer 117ºC for the noon-time equatorial temperature. (I'm hoping the concept of 'equator' does not clash with your 'flat Earth' beliefs.)

     However, you do rather queer you own pitch with your reference to Earthly temperatures. With a Lunar day lasting ~29 days, Lunar temperatures at noon are not far off that of steady-state. This is far from true on Earth. So when you state "we get a higher night temp but that is the result of cooling, not warming,"  this is of course correct. But critically you must account for the 'something'  that is "cooling"  which allows the night-time to be 'warmed'. That 'something' would be the day-time. (Thankfully, flat Earth theory does not refute the existance of night & day so that should make sense to you.) Warmer nights due to cooler days. Simples.

122. fake reality at 03:19 AM on 20 July, 2016

     @110

     There is no balance at the top. 1370W/m^2 going in and a tenth of that going out. If you want you can double OLR from 220K or whatever value you use, since it represents the amount absorbed in 1m^2 from solar irradiation when it is emitted from twice the surface area. That doesn´t help much though, it´s not possible to find any balance in those numbers. And of course we should not expect to, earth is not a lossles system, it leaks energy at every point of absorption and emission as it is a greybody and not a blackbody.

     A greybody is defined by it´s lacking ability to convert irradiation into  radiation. It is cooler than a blackbody.

     You might be right in that more co2 would increase height of tropopause, but wrong in the assumption that it would affect surface temperature. Everything radiates according to it´s own temperature. That temperature might be the product of heat from a more intense source, but it never is a product of a less intense source.

     You claim that earth surface radiates with an intensity that is influenced by a cold body absorbing heat in it´s radiation field. That is in direct opposition to what we know of heat transfer, that the rate is the difference in T and that the hot body never changes in temperature even when the absorber has reached an equally excited state.

     In fact, when you want to increase heat transfer from the hot body, one method is to add another surface that absorbs energy and radiates more energy from a larger surface area. Then more energy will transfer to the surroundings, in this case that is the optimal heat sink in 3K space vacuum.

     Ooops, I just said that according to heat transfer as heat and thermal radiation in theory and practice, the atmosphere increase heat transfer to space. Well, that is in line with science and we don´t need to violate it with horrific ideas about how much cold we need to get something warm.

     Where did you get the idea that the surface is communicating with TOA about what balance needs to be attained. The surface radiates according to it´s own temperature, as everything does, and the surface temperature is the suns. It radiates as a greybody in relation to the sun, and the atmosphere radiates in longwave as a greybody in relation to earth, and through the earth it radiates as a greybody in relation to the sun.

     The atmosphere radiates according to what it receives. And in heat transfer we learn that even if photons might be funny little things, they should never be included in calculations of heat transfer as heat or thermic radiation. That would give the wrong results.

     Still, that is just what you do.

     Another detail is that all radiation in earth system is thermic radiation, from visible at 500nm through the whole spectrum of IR. It is a product of temperature/heat. The hotter the brighter.

     Why would an intensity of 250K/300W in the atmosphere add anything to the 1000W we get from the sun? It is not a question of the numbers adding up to more energy, it is about excitance of matter.

     The maxwell-boltzmann distribution tells us that a temperature is a measure of the probability of different states of excitance=levels of energy in a particle/photon. The higher temperature having more probable states of higher energy in more photons/particles. So you can see why a 100 sources of radiation at 250K will not give a higher probability for higher states in particles/photons. Much less an icecold atmosphere in relation to a hot surface, it actually decrease overall probability of higher states. That is cooling.

     Only something hotter can increase temperature of a body in an open system.

123. fake reality at 03:36 AM on 20 July, 2016

     @121 MA rodger

     Do you realize what you just did there?  You were trying to discredit me by attaching a belief in unscientific theorys to my character. That is very bad behaviour, you should keep to the things discussed. That was bad rethoric.

     You dont understand the simple concept that radiation absorbed at any surface area from solar irradiation, is emitted from twice that area?

     Are you saying that the earth is not cooled by half and heated by half?

     And about measured values, 1000W/m^2 is a common value in a pretty big area from the equator and outward towards the poles. It represents a mean value uf emitted intensity since it is absorbed as a ~maximum and will distribute through the earth evenly and emitted from twice that area.

     That makes it the value defining the maximal averaged intensity possible=mean temperature emitted.

     So I am using measured values, when I use 1000W/m^2. 

     About the 130degrees on the moon, 117 is even closer to my calculation. So you prove my point. And please stop attacking my character by attaching views to me that I don´t have.

     I got a warning further up for being snarky, if the mod is not biased you will have one for this.

     "you must account for the 'something' that is "cooling" which allows the night-time to be 'warmed'."

     This is why I get snarky. I gave you numbers in calculations and instead of addressing that with scientific arguments, you talk about "something" "allowing" something else to be "warmed".

     Do you realize how far from science such an argument is?

     Response:

     [JH] Moderation complaints are prohibited and will be summarily deleted per the SkS Comments Policy.

     In order to be taken seriously on this website, you must document the sources of the information you present. You have not done so in either this comment or in previous comments. Without documentation, you are merely expressing your personal opinion which carries very little weight in a serious discussion about science.

124. michael sweet at 04:03 AM on 20 July, 2016

     Fake,

     It is common knowledge that for a spherical object you have to devide the cross-sectional radiation by four, not two times.  That means the incident radiation is about 240 w/m2, not 400 as you calculate.  It follows that if you cannot calculate the incident radiation within a factor of two, your calculation of the temperature is grossly in error.  Since you were so assertive that you are correct and the rest of the world is stupid, MA Rodgers probably thought it was a waste of time to engage you and discuss the actual calculations.

     If you want to drop your attitude and ask how you came to have such absurd ideas there are people at this site who would help you to understand what the real data calculations are.   If you continue to insist your incorrect calculations are correct I doubt many will engage with you.  Ask quesitons about those ideas you do not understand.  If you think you have discovered an error everyone else is making consider that you probably have made another basic math error.

125. fake reality at 05:11 AM on 20 July, 2016

     @125

     I know how and why you do it that way. But since flux density is not linear it is the wrong way to handle it. And most of all, if there is a way to calculate with measured values at the surface, and that gives you the right number immediately, then you know that it is right. The main point is real observed flux density at the surface.

     Do you agree that dividing by four is equal to 4 weak suns @ 250-ish K?

     Do you agree that maxwell-boltzmann is correct about energycontent in matter by describing the probability of diffrent states of excitance in matter, is correct?

     If you do, then you should agree that it is the wrong approach to divide flux density en four equal smaller suns that each has the same probability for a certain exited state in matter, and that it is the same when they all is added as irradiative flux at their respective m^2.

     And you would also agree that a single sun at the same fluxdensity as the sum of the 4 suns, will deliver a flux density to the total surface area in one irradiated m^2 that is emitted radiation from 2m^2 surface.

     It´s not like I´m making numbers up here, they are real measured values at the surface. If I´m remembering right solar cells are calibrated to 1kW. There is of course a real reason for that.

     Your number is not real, it may be measured in a cold place sometimes, but a uniform value of 240W is not more than sunlight worth of 255K from all directions at the surface. You must realize that 255K irradiating the earth from all directions heats the surface less than 1000W in one direction.

     I think I wrote wrong value earlier, 1000W=364K nothing else. If I have written 390K somewhere that is the value of TSI-1370W.

     Show me where the absurdity comes from in my calculation. Then show me what is not absurd in calculating the temperature with a value that is way off from observations in reality.

     I get the right number at the surface. You get the wrong number. Isn´t the absurd residing in you saying that your number, that we know is not right from observations, is more valid than my calculation that use measured value from real observation that is documented?

     We have measured 1000W/1m^2 at the surface, it is absolutely right to use that number emitted as /2m^2 when calculating OLR. And since we agree on OLR surface flux at about 400W, we can use real observed emissivity as well. All real values from reality, and it gives the right surface temp. You have 4 suns evenly heating 4 m^2 each with 255K=240W, and you say that it should be equal to 1000W/m^2 which comes from 1370W at TOA, same as you are using.

     You are saying that 240W/m^2 is equal to 1000W/m^2 that is averaged as 400W/m^2 when emitted by double the size Area?

     What is real about that?

     I have this attitude as I have seen your collective attitude against the ones not agreeing with you. My comments is nothing compared to that I was attacked above when I was assigned the belief in a flat earth. That is really low rethoric.

     I am very sure that I didn´t make an error since I use real measured values and get the correct results. And I am sure that the basic math error is made in your theorys calculation since it is not anything real about 4 weak suns heating the earth to 255K with 240W/m^2.

     But OK,if you want questions I can ask: where did you get the idea that 240W/m^2 from 4 suns irradiating 4m^2 is equal to 1370W/m^2  in heat transfer, since temperature and Watt/m^2 is not linear?

     Why do you use an absorbing body at a low temperature in earths radiation field for heat transfer to the surface, when we know that heat transfer from a warm to a cold body is something that only affects the cold body?

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